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The coercivity of a small magnet where the ferromagnet gets demagnetised is 3 xx 10^(3) A//m. The current required to be passed in a solenoid of length 10 cm and number of turns 100, so that the magnet gets demagnetised when placed inside the solenoid is |
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Answer» 30 mA The coercivity of `3 xx 10^(3) A//m` of the MAGNET implies that a magnetic field of intensity `H = 3 xx 10^(3) A//m` should be APPLIED in opposite direction to demagnetise the magnet. For a solenoid, `B = mu_(0)H` but `B = mu_(0)H` `therefore H = ni` In this case , `N = (1000)/(10cm)= (100)/(10xx10^(-2)m) = 1000 "turns"//m` `:. i = H/n = (3 xx10^(3))/(1000) = 3A` |
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