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The cofficient of performance of a refrigerator is 5. If the temperature inside freezer is `-20^(@)C`, the temperature of the surroundings to which it rejects heat is :A. `21^(@)C`B. `31^(@)C`C. `41^(@)C`D. `11^(@)C` |
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Answer» Correct Answer - B Coefficient of performance of refregetor `COP = (T_L)/(T_(H)-T_(L))` Where `T_(L) rarr` lower temperature and `T_(H) rarr` higher temperature so, `5=(T_L)/((T_(H)-T_(L))` `implies T_(H) = 6/5T_(L)=6/5(253)=303.6K`. |
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