1.

The coherent point sources `S_(1)` and `S_(2)` vibrating in same phase emit light of wavelength `lambda`. The separation between the sources is `2lambda`. Consider a line passingh through `S_(2)` and perpendicular to the line `S_(1)S_(2)`. What is the smallest distance from `S_(2)` where a minimum of intensity occurs due to interference of waves from the two sources?

Answer» At` S_2, Deltax= 2lambda`
Therefore, the minima closest to `S_2` will be corresponding to the path
difference `Deltax = (3lambda)/2`. Suppose this point is P at a distance y from `S_2`.Then,
`S_1P - S_2P = (3lambda)/2`
`sqrt(y^2 + (S_1 S_2)^2) -y = (3lambda)/2`
or ` sqrt(y^2+(2lambda)^2) = (y + (3lambda)/2)`
Squaring and then solving this equation, we get
`y= (7lambda)/12`.


Discussion

No Comment Found

Related InterviewSolutions