1.

The combined resistance of a galvanometer of resistance `500 Omega` and its shunt is `21 Omega` Calculated the value of shunt.

Answer» Here, `G = 500 Omega` and `R_(eq)= 21 Omega`
`1/(R_(eq)) = 1/G +1/S`
`:. 1/S = 1/(R_(eq)) - 1/G = (G-R_(eq))/(R_(eq)G)`
`:. S = (R_(eq)G)/(G-R_(eq))`
`rArr S = (500 xx 21)/(500 - 21) = (10500)/(479)`
`:. S = 21.92 Omega`.


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