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The combined resistance of a galvanometer of resistance of `495` ohm and its shunt is `9.9 Omega` . The shunt resistance isA. `1.01Omega`B. `8.9Omega`C. `10.1Omega`D. `9.1Omega` |
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Answer» Correct Answer - C `R_A =(GS)/(S+G)` `9.9 S +495xx9.9 = 495 S S =(495xx9.9)/(485.1)=10.1Omega `. |
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