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The common difference of an anthmetic sequence is1 and the product of the first and the third terms is143. What are the first three terms? |
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Answer» Step-by-step explanation: Let FIRST term be (a-d), a, (a+d) (a-d) (a+d)=143 since d=1 (a-1) (a+1)=a^2-1=143 a^2=144 a=+12 or -12 if a=+12 then AP=11,12,13 if a= -12 then AP= -13,-12,-11 go for it DUDE..... |
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