

InterviewSolution
Saved Bookmarks
1. |
The component of `vecA` along `vecB` is `sqrt(3)` times that of the component of `vecB` along `vecA`. Then A:B isA. `1:sqrt(3)`B. `sqrt(3):1`C. `2:sqrt(3)`D. `sqrt(3):2` |
Answer» Correct Answer - B `A cos theta=(vecA.vecB)/(|vecB|)` and `B cos theta=(vecA.vecB)/(|vecA|)`, `A cos theta=sqrt(3) B cos theta` |
|