1.

The compound interest on Rs. 4000 at 10% per annum for 2 years 3 months, compounded annually, is A. Rs. 916 B. Rs. 900 C. Rs. 961 D. Rs. 896

Answer»

Present value, P = Rs.4000 

Interest rate, R = 10% per annum 

Time, n = 2 years 3 months = (2 + 1/4) years 

∴ Amount (A) = P (1 + R/100)n × [1 + (R/4)/100] [Where, P = Present value 

R = Annual interest rate 

n = Time in years] 

∴ A = 4000 (1 + 10/100)2 × [1 + (10/4)/100] 

⇒ A = 4000 (1 + 1/10)2 × [1 + 1/40] 

⇒ A = 4000 (11/10)2 × [41/40] 

⇒ A = 4000 × 121/100 × 41/40 

⇒ A = 40 × 121 × 41/40 

⇒ A = 121 × 41 

⇒ A = 4961 

∴ Amount = Rs.4961 

∴ Compound interest = Rs.(4961 – 4000) [∵CI = A – P] 

= Rs.961



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