1.

A machine is purchased for Rs. 625000. Its value depreciates at the rate of 8% per annum. What will be its value after 2 years?

Answer»

Present value of machine, P = Rs.625000 

Time, n = 2 years 

Rate of depreciates, R = 8% per annum 

Now, 

Amount (A) = P (1 + R/100)n [Where, A = Amount with compound interest 

P = Present value 

R = Annual interest rate 

n = Time in years] 

∴ Value = P (1 - R/100)n [∵ Rate decreases] 

= 625000 (1 - 8/100)2 

= 625000 (1 - 2/25)2 

= 625000 (23/25)2 

= 625000 × 729/625 

= 1000 × 529 

= 529000 

∴ Value of machine after 2 years will be Rs.529000.



Discussion

No Comment Found

Related InterviewSolutions