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A machine is purchased for Rs. 625000. Its value depreciates at the rate of 8% per annum. What will be its value after 2 years? |
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Answer» Present value of machine, P = Rs.625000 Time, n = 2 years Rate of depreciates, R = 8% per annum Now, Amount (A) = P (1 + R/100)n [Where, A = Amount with compound interest P = Present value R = Annual interest rate n = Time in years] ∴ Value = P (1 - R/100)n [∵ Rate decreases] = 625000 (1 - 8/100)2 = 625000 (1 - 2/25)2 = 625000 (23/25)2 = 625000 × 729/625 = 1000 × 529 = 529000 ∴ Value of machine after 2 years will be Rs.529000. |
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