1.

A scooter is bought at Rs. 56000. Its value depreciates at the rate of 10% per annum. What will be its value after 3 years?

Answer»

Present value of scooter, P = Rs.56000 

Time, n = 3 years 

Rate of depreciates, R = 10% per annum 

Now, 

Amount (A) = P (1 + R/100)n [Where, A = Amount with compound interest 

P = Present value 

R = Annual interest rate 

n = Time in years] 

∴ Value = P (1 - R/100)n [∵ Rate decreases] 

= 56000 (1 - 10/100)3 

= 56000 (1 - 1/10)3 

= 56000 (9/10)3 

= 56000 × 729/1000 

= 56 × 729 

= 40824 

∴ Value of scooter after 3 years will be Rs.40824.



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