1.

the compound interest on rupees 24000compounded semi annual ly for 3/2 yearsat the rate of 10 %per annum is​

Answer»

Compound Interest (CI) = 3783/-Step-by-step explanation:P = 24000/-r = 5%t = 3/2×2 = 3 (Half yearly)A = P(1+r/100)^n = 24000(1+5/100)³ = 24000×21/20×21/20×21/20 = 27783Compound Interest = A - P = 27783 - 24000 = 3783/-In this question I think the rate of interest is 5% not 10%but you can check from this answer and can solve your sum.Hope it helps you ^_^PLS MARK my answer as BRAINLIEST and follow me. ^_^



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