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The concentration of a solution having concen-tration 0.24 Mis reduced to 0.12 M in 10 hoursand 0.06 M in 20 hours. What is the rate con-stant of the reaction? (471 ua shoot ge 10- - - - - - - - - --- - |
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Answer» k=2.303/t *log[R]/[R1] where t=10 hours [R]=0.24 and [R1]=0.12 ALSO, k=2.303/t1 *log[R]/[R2] where t=20 hours [R]=0.24 and [R1]=0.6 on adding the above equations, 2k=0.0693203+0.069377 k=0.1386973 or 0.14 |
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