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The concentration of solutions can be expressed in number of ways such that Normality, Molarity, Molality, Mole fractions, Strength, `%` by weight, `%` by volume and `%` by strength. The molarity of ionic compound is usually expressed as formality beacuse we use formula weight of ionic compound. Addition of water to a solution changes all these terms, however increase in temperature does not change molality, mole fraction and `%` by weight terms. Volume of water required to convert `100 mL 0.5M NaOH` solutions to `0.2M NaOH` solution is:A. `250 mL`B. `150 mL`C. `100 mL`D. `400 mL` |
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Answer» Correct Answer - C Meq.of.dil. `NaOH= "Meq.of conc."NaOH` `0.2xxV=0.5xx100` `therefore V=250 mL` `therefore H_(2)O` needed `=250-100=150 mL` |
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