1.

The conductivity of `0.1`m KCl solution is `1.29sm^(-1)`. If the resistance of the cell filled with `0.1` M KCl is 100 ohm. Calculate the cell constant.

Answer» `k=GxxG^(**)rArrk=(1)/(R)xxG^(**)`
`G^(**)=kxxR=1.29xx100=129cm^(-1)`


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