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The conductivity of 0.1 n NaOH solution is 0.022 S`cm^(-1)`.When equal volume of 0.1 N HCl solution is added, the conductivity of resultant solution is decreased to 0.0055 S `cm^(-1)` . The equivalent conductivity in `Scm^(2)equi^(-1)` of NaCl solution is :A. `0.0055`B. `0.11`C. 110D. 55 |
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Answer» Correct Answer - C Normality of resulatant solution of `=(0.1xxV)/(VxxV)=0.05N` `Lambda_(eq)=1xx(0.0055)/(0.05)="110 S cm"^(2)eq^(-1)` |
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