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The conductivity of a material with current density 1 unit and electric field 200 μV is(a) 2000(b) 3000(c) 4000(d) 5000This question was posed to me during a job interview.This intriguing question originated from Stokes Theorem topic in portion Vector Calculus of Electromagnetic Theory

Answer»

The correct choice is (d) 5000

The explanation is: The current density is GIVEN by, J = σE. To find conductivity, σ = J/E = 1/200 X 10^-6 = 5000.



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