1.

The constant-current region of a JFET lies between__________(a) Cut off and saturation(b) Cut off and pinch off(c) 0 and IDSS(d) Cut off and breakdownThis question was posed to me during an internship interview.Question is taken from Transconductance Amplifiers in section Differential and Multistage Amplifiers of Electronic Devices & Circuits

Answer»

Correct option is (d) Cut off and breakdown

Easy explanation: Value of drain-source voltage, VDS for breakdown with the INCREASE in negative bias voltage is reduced simply due to the FACT that gate-source voltage, VGS keeps adding to the reverse bias at the junction PRODUCED by CURRENT flow. Thus the current flow remains constant between the cut off and breakdown REGION of JFET.



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