The constant of a thermocouple is 7.6mu V//K, the temperature of its cold junction is -80^(@)C (dry ice), and that of the hot 327^(@)C (molten lead). What charge will flow through the thermocouple, if the hot junction absorbs quantity of heat equal to one joule? The efficiency of the thermocouple is 20%.

The constant of a thermocouple is 7.6mu V//K, the temperature of its c

1.	The constant of a thermocouple is 7.6mu V//K, the temperature of its cold junction is -80^(@)C (dry ice), and that of the hot 327^(@)C (molten lead). What charge will flow through the thermocouple, if the hot junction absorbs quantity of heat equal to one joule? The efficiency of the thermocouple is 20%.
Answer» Solution :A thermocouple may be regarded as a heat engine working in the temperature range from `T_(1)` to `T_(2)`, where the indices 1 and 2 refer to the hot and the cold junctions. When a charge passes through a thermocouple, WORK is performed equal to `W=etaQ_(1)`. The TRANSPORTED charge is `q=W/(E)=(etaQ_(1))/(alpha(T_(1)-T_(2)))`

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