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The conversion of `A rarr B` follows second-order kinetics. Doubling the concentration of `A` will increase the rate of formation of `B` by a factorA. `1//4`B. `2`C. `1//2`D. `4` |
Answer» Correct Answer - D `r = k(A)^(2)`, when concentration is doubled `r = k(2A)^(2) = k4(A)^(2)` the rate becomes `4` times. |
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