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The correct of decreasing second ionisation enthalpy of `Ti(22),V(23),Cr(24)` and `Mn(25)` isA. `Mn gt Cr gt Ti gt V`B. `Ti gt V gt Cr gt Mn`C. `Cr gt Mn gt V gt Ti`D. `V gt Mn gt Cr gt Ti` |
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Answer» Correct Answer - C As ionization enthalpy (both first and second) increases from left to right across the period. Only chromium is exceptional due to the stable configuration `(3d^(5))` so the correct order is : `Crgt Mn gt V gt Ti` |
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