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The correct of decreasing second ionisation enthalpy of `Ti(22),V(23),Cr(24)` and `Mn(25)` isA. `Ti gt V gt Cr gt Mn`B. `Cr gt Mn gt V gt Ti`C. `V gt Mn gt Cr gt Ti`D. `Mn gt Cr gt TI gt V` |
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Answer» Correct Answer - B In general, ionization enthalpy increases as we move across the period on account of increases of effective nuclear charge. But Cr has unsually high `Delta_(i)H_(2)` on account of extra stability of `d^(5)` configuration of `Cr^(+)` ion. Thus, the correct order is `Cr gt Mn gt V gt Ti` |
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