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The correct order for bond angles is :A. `NO_2^+ gt NO_2gtNO_2^-`B. `No_2^+ gt NO_2^- gtNO_2`C. `NO_2 gtNO_2^- gtNO_2^+`D. `NO_2^- gtNO_2 gtNO_2^+` |
Answer» Correct Answer - A Each has `sp^2` -hybridsation having one lone pair on ` N` in `NO_2^+`, one lone paire and one unshared pair of elctron on N in `NO_2` and tow lone pair of electrons in ` NO_2^-`. Thus bond angles are ` NO_2^+ gt NO_2 gt NO_(2)^(-) :: 180^@ gt 132^@ gt 115^@`. |
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