The correct order of N-compounds in its decreasing order of oxidation states isA. `HNO_(3), NH_(4)Cl,NO,N_(2)`B. `HNO_(3),NO,NH_(4)Cl, N_(2)`C. `HNO_(3),NO,N_(2),NH_(4)Cl`D. `NH_(4)Cl,N_(2),NO,HNO_(3)`

The correct order of N-compounds in its decreasing order of oxidation

1.	The correct order of N-compounds in its decreasing order of oxidation states isA. `HNO_(3), NH_(4)Cl,NO,N_(2)`B. `HNO_(3),NO,NH_(4)Cl, N_(2)`C. `HNO_(3),NO,N_(2),NH_(4)Cl`D. `NH_(4)Cl,N_(2),NO,HNO_(3)`
Answer» Correct Answer - C Let the oxidation state of nitrogen in each of the given N-compounds be x. `(i) HNO_(3) : +1+x+3(-2)=0` x=+5 `therefore` Oxidation state of N in `HNO_(3)` is +5. (ii) `NO : x+1(-2)=0` x=+2 `therefore` Oxidation state of N in NO is +2 `(iii) NH_(4)Cl : x+4(+1)+1(-1)=0` x= -3 `therefore` Oxidation state of N in `NH_(4)Cl` is -3. `(iv) N_(2) : x=0 [ therefore N_(2)` is present in elemental state] `therefore` Oxidation state of N in `N_(2)` is 0. Thus, the correct decreasing order of oxidation states of given N - compounds will be `overset(+5)(HNO_(3)) gt overset(+2)(NO) gt overset(0)(N_(2)) gt overset(-3)(NH_(4)Cl)`

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The correct order of N-compounds in its decreasing order of oxidation states isA. `HNO_(3), NH_(4)Cl,NO,N_(2)`B. `HNO_(3),NO,NH_(4)Cl, N_(2)`C. `HNO_(3),NO,N_(2),NH_(4)Cl`D. `NH_(4)Cl,N_(2),NO,HNO_(3)`

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