InterviewSolution
Saved Bookmarks
| 1. |
The correct relation between the emitter current Ie and the base current Ib is given by(a) Ib = (1 + α) Ie(b) Ib = (α – 1) Ie(c) Ie = (1 – ß) Ib(d) Ie = (1 + ß) IbI had been asked this question by my college director while I was bunking the class.This is a very interesting question from BJTs Current-Voltage Characteristics in section Bipolar Junction Triodes (BJTs) of Electronic Devices & Circuits |
|
Answer» Correct CHOICE is (d) Ie = (1 + ß) Ib |
|