The correct relationship between free energy change in a reaction and the corresponding equilibrium constant `K_(c)` is:A. `DeltaG^(@)=RT ln K_(c)`B. `-DeltaG^(@)=RT lnK_(c)`C. `DeltaG=RT ln K_(c)`D. `-DeltaG=RT lnK_(c)`

The correct relationship between free energy change in a reaction and

1.	The correct relationship between free energy change in a reaction and the corresponding equilibrium constant `K_(c)` is:A. `DeltaG^(@)=RT ln K_(c)`B. `-DeltaG^(@)=RT lnK_(c)`C. `DeltaG=RT ln K_(c)`D. `-DeltaG=RT lnK_(c)`
Answer» Correct Answer - b `DeltaG=DeltaG^(@)+RTln Q`, Where `Q` is reaction quotient , At equibrium `DeltaG=0` and `Q=K_(c) :. -DeltaG^(@)=RT ln K_(c)`

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The correct relationship between free energy change in a reaction and the corresponding equilibrium constant `K_(c)` is:A. `DeltaG^(@)=RT ln K_(c)`B. `-DeltaG^(@)=RT lnK_(c)`C. `DeltaG=RT ln K_(c)`D. `-DeltaG=RT lnK_(c)`

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