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| 1. |
The correct sequence of arrangement of the following compounds in order of decreasing oxidation numbers of iodine is 1. HIO4 , HI , I2 ICl5 2. HIO4 , ICl5 , HI , I2 3. ICl5 , HIO4 , I2 HI 4. HIO4 , ICl5 , I2 , HI |
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Answer» 4. HIO4 , ICl5 , I2 , HI |
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