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The correct stability order for `N_2` and its given ions is :A. `N_2 gt N_2^+ gtN_2^-1 gt N_2^(2-)`B. `N_2 lt N_2^+ ltN_2^-1 lt N_2^(2-)`C. `N_2 gt N_2^+ ltN_2 gt N_2^(2)`D. `N_2gt N_2^+ = N2^- gt N_2^(2-)` |
Answer» Correct Answer - A M.O. configuration of `N_2 : sigma 1s^2 , sigma^(**) 1s^2` . ` sigma s^2 , sigma2s^2 , [( pi 2 p_y^2) ,(pi2p_z^2)] sigma2p_x^2` The bond order for `N_2 =3` Fro `N_2^+ = 5/2` , For `N_2^- = 5/2` (with one moer antibonding electron than ` N_2^(+)` and 2 presoectivley . Thus Thus bond order is `N_2 gt N_2^+ = N_2^- gt N_2^(2-)` and stability order will be ` N_2 gt gt N_2^+ gt N_2^- gt N_2^(2-)`. |
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