1.

The cost of electricity required to deposit 1 g of Mg is Rs.3.00. The cost of deposit 8 g of Al is (al.mass Al = 27 , Mg = 24)

Answer»

RS.`12.00`
Rs. `24.00`
Rs. `32.00`
Rs.`42.50`

SOLUTION :`(W_(Al))/(W_(Mg)) = (E_(Mg))/(E_(Al))`
`therefore (W_(Al))/(1)= (24//2)/(27//3) = (12)/(9)`
`therefore W_(Al) = (12)/(9)` gms.
When 1 gm of Mg deposited at the same time , `(12)/(9)` gm of Al deposited by passing same quantity of ELECTRICITY
For 1 gm Mg `-=` it cost three rupees
`therefore (12)/(9) g Al -= x : x = (3 xx (12//9))/(1) = 4` rupees
`therefore` For 8 gm of Al `-= 8 xx 4 = 32` rupees


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