1.

The cost of table salt (NaCl) and table sugar (C_(2)H_(22)O_(11)) is Rs. 2 per kg and Rs. 6 per kg respectively. Calculate their costs per mole.

Answer»


Solution :1 MOLE of NaCl = 58.5 g
`THEREFORE"Cost of NaCl per mole"=(2)/(1000)xx58.5"Rs. = 0.117 Re = 11.7 p = 12p."`
1 mole of sugar `(C_(12)H_(22)O_(11))=342g`
`therefore"Cost of sugar per mole"=(6)/(1000)xx342"Rs. = Rs. 2.05 p."`


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