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The critical angle for two media with permittivities of 16 and 9 respectively is(a) 48.59(b) 54.34(c) 60(d) 45This question was addressed to me in class test.My doubt stems from Snell Law and Critical Angle in section EM Wave Propagation of Electromagnetic Theory |
Answer» CORRECT option is (a) 48.59 To elaborate: The sine of the critical ANGLE is the ratio of refractive index of MEDIUM 2 to that in medium 1. Thus SIN θc = n2/n1. Also n = √ε, thus sin θc = √ε2/√ε1. Put ε1 = 16 and ε2 = 9, we GET θc = sin^-1(3/4) = 48.59 degree. |
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