1.

The critical angular for a particular medium is sin^(-1)((3)/(5)) , then how much is the angle of polarisation in that medium ?

Answer»

`sin^(-1)((4)/(5))`
`TAN^(-1)((5)/(3))`
`tan^(-1)((3)/(4))`
`tan^(-1)((4)/(3))`

Solution :`theta=sin^(-1)((3)/(5))`
`:.sin theta=(3)/(5)`
`:. (1)/(n)=(3)/(5)`(From total internal reflection)
`:.n=(5)/(3)`
Now from Brewster.s LAW,
`n=tan theta_(p)`
`:. theta_(p)=tan^(-1)(n)`
`:. theta_(p)=tan^(-1)((5)/(3))`


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