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The critical speed of a satellite orbiting very close to the surface of the earth is `[g=10 m//s^(2)` and `R=6.4xx10^(-6)m]`A. `8xx10^(3)m//s`B. `4xx10^(3)m//s`C. `16xx10^(4)m//s`D. `2xx10^(4)m//s` |
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Answer» Correct Answer - A For a satellite orbiting very close to the surface of the earth, the critical speed, `v_(e )=sqrt((GM)/(R ))` but `GM = gR^(2)` `therefore v_(C )=sqrt((gR^(2))/(R ))=sqrt(gR)=sqrt(10xx6.4xx10^(6))` `therefore v_(C )=sqrt(64xx10^(6))=8xx10^(3)m//s` |
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