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The cross product of the vectors 3i + 4j – 5k and –i + j – 2k is,(a) 3i – 11j + 7k(b) -3i + 11j + 7k(c) -3i – 11j – 7k(d) -3i + 11j – 7kThis question was posed to me by my college professor while I was bunking the class.This question is from Dot and Cross Product in portion Vector Analysis and Applications of Electromagnetic Theory

Answer»

Correct option is (b) -3i + 11j + 7k

Easiest explanation: Cross product of two vectors is, A X B = (A2*b3 – b2*a3)i – (a1*b3 – B1*a3)J + (a1*b2 – b1*a2)K. Using the formula, the answer can be calculated.



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