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The CT for an abrupt PN junction diode is ________(a) CT = K/(V0+VB)^1/2(b) CT = K/(V0+VB)^-1/2(c) CT = K/(V0+VB)^1/3(d) CT = K/(V0+VB)^-1/3I had been asked this question by my college professor while I was bunking the class.This interesting question is from Diode Capacitances topic in portion Semiconductor-Diode Characteristics of Electronic Devices & Circuits |
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Answer» RIGHT CHOICE is (a) CT = K/(V0+VB)^1/2 The explanation: For an abrupt PN junction diode, CT = K/(V0+VB)^n. Here,n=1/2 for abrupt PN junction diode and 1/3forlinear PN junction diode. When the doping concentration of a diode VARIES within a SMALL scale of area, then the diode is called as an abrupt diode. |
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