1.

The CT for an abrupt PN junction diode is ________(a) CT = K/(V0+VB)^1/2(b) CT = K/(V0+VB)^-1/2(c) CT = K/(V0+VB)^1/3(d) CT = K/(V0+VB)^-1/3I had been asked this question by my college professor while I was bunking the class.This interesting question is from Diode Capacitances topic in portion Semiconductor-Diode Characteristics of Electronic Devices & Circuits

Answer» RIGHT CHOICE is (a) CT = K/(V0+VB)^1/2

The explanation: For an abrupt PN junction diode, CT = K/(V0+VB)^n. Here,n=1/2 for abrupt PN junction diode and 1/3forlinear PN junction diode. When the doping concentration of a diode VARIES within a SMALL scale of area, then the diode is called as an abrupt diode.


Discussion

No Comment Found

Related InterviewSolutions