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The current element of the solenoid of turns 100, length 2m and current 0.5A is given by,(a) 100 dx(b) 200 dx(c) 25 dx(d) 50 dxI had been asked this question in a national level competition.My question is taken from Biot Savart Law topic in portion Magnetostics of Electromagnetic Theory

Answer» CORRECT answer is (c) 25 dx

The EXPLANATION is: The CURRENT ELEMENT of the solenoid is given by NI dx/L. Put N = 100, I = 0.5 and L = 2 to get, I dx = 100 x 0.5 x dx/2 = 25 dx.


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