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                                    The current flows in the wire from `A` to `D` clockwise direction. The net force on `ABCD` A. `(sqrt(17))/(2)BiR`B. `(sqrt(15))/(2)BiR`C. `(sqrt(13))/(2)BiR`D. `B i R` | 
                            
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Answer» Correct Answer - A `F_(AB) = B i R`, towards left `F_(BC) = Bi.2R = 2BiR`, upwards `F_(CD) = (BiR)/(2)`, towards right `F_(n et) = sqrt((BiR - (BiR^(2))/(2))^(2) + (2BiR)^(2)) = (sqrt(17) BiR)/(2)`  | 
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