1.

The current gain of a common emitter transiter circuit shown in figureis. Drawthedc load line andmark the Q point on it .

Answer»

SOLUTION :`BETA=120`
Base CURRENT`I_B=(25V)/(1MOmega)=(25)/(1xx10^6)=25muA`
`beta=(I_C)/(I_B),I_C=betaI_B`
`I_C=120xx25muA`
`I_C=3mA`
`V_CE=V_CC-I_CR_C`
`V_CE=25-3mAxx5k`
`V_CE=10V`


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