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The current I passed in any instruement in alternating current circuit is I = 2 sin omegat amp and potential difference applied is given by V = 5 cos omegat volt then power loss in instruement is |
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Answer» 2.5 watt `V = 5 cos omega t = 5 sin ((pi)/(2) - OMEGAT)`Since, there is a phase difference of `(pi)/(2)` between the current and VOLTAGE `therefore` AVERAGE POWER over a COMPLETE cycle is zero. |
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