1.

The current in the primary circuit of a potentiometer wire is 0.5 A. Specific resistance of wire is 4 xx 10^(-7) Omega m and area of cross section of wire is 8 xx 10^(-6) m^(2). The potential gradient on the wire would be

Answer»

2.5 m V/m
25 mV/m
25 V/m
10 V/m

Solution :25 mV/m
POTENTIAL gradient `sigma= (I rho)/(A) = (0.5 xx 4 xx 10^(-7))/(8 xx 10^(-6))`
`therefore sigma = 0.25 xx 10^(-1) = 25 xx 10^(-3)`
`therefore sigma = 25 ` m V/m


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