The current voltage relation of diode is given by I=(e^(1000V//T)-1) mA , where the applied voltage V is in volts and the temperature T is in degree Kelvin . If a student makes an error measuring pm0.01 V while measuring the current of 5 mA at 300K, what will be the error in the error in the value of current in mA ?

The current voltage relation of diode is given by I=(e^(1000V//T)-1) m

1.	The current voltage relation of diode is given by I=(e^(1000V//T)-1) mA , where the applied voltage V is in volts and the temperature T is in degree Kelvin . If a student makes an error measuring pm0.01 V while measuring the current of 5 mA at 300K, what will be the error in the error in the value of current in mA ?
Answer» 0.5 mA 0.05 mA 0.2 mA 0.02 mA Solution :`5 = e^(100 (V)/(T))-1` `impliese^(1000V/T=6)""....(1)` Again , `I=e^(1000V/T)-1` `(dI)/(DV)=e^((1000V)/T)1000/T` `dI=1000/Te^(1000/TV)dV` Using (1) , `DeltaI=100/Txx6xx0.01` `=60/T=60/(300)=0.2mA` So correct choice is (C) .

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