The cut off frequency of the TE01 mode will be(a) mc/2a(b) mc/2b(c) nc/2a(d) nc/2bI have been asked this question in unit test.This key question is from Cut-off Frequency and Wavelength in section Waveguides of Electromagnetic Theory

The cut off frequency of the TE01 mode will be(a) mc/2a(b) mc/2b(c) nc

1.	The cut off frequency of the TE01 mode will be(a) mc/2a(b) mc/2b(c) nc/2a(d) nc/2bI have been asked this question in unit test.This key question is from Cut-off Frequency and Wavelength in section Waveguides of Electromagnetic Theory
Answer» Correct option is (d) nc/2b To explain: The CUT off frequency CONSISTS of modes m and n. For m = 0, the DIMENSION B will be CONSIDERED. Thus the frequency is nc/2b, where c is the speed of the light.

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The cut off frequency of the TE01 mode will be(a) mc/2a(b) mc/2b(c) nc/2a(d) nc/2bI have been asked this question in unit test.This key question is from Cut-off Frequency and Wavelength in section Waveguides of Electromagnetic Theory

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