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The cut off wavelength of the TE10 mode having a broad wall dimension of 5cm is(a) 0.1(b) 1(c) 10(d) 0.01This question was posed to me in unit test.This question is from Cut-off Frequency and Wavelength topic in division Waveguides of Electromagnetic Theory

Answer»

The CORRECT answer is (a) 0.1

Easiest explanation: The cut off wavelength of the waveguide is given by λc = 2a/m. on substituting for a = 0.05 and m = 1, we get λc = 2 x 0.05/1 = 0.1 UNITS.



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