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The de Broglie wavelength is given byA. `p=(2pih)/(lamda)`B. `p=(h)/(2lamda)`C. `p=(2pi)/(hlamda)`D. `p=(2pi)/(lamda)` |
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Answer» Correct Answer - A (a) : de Broglie wavelength is given by `lamda=(h)/(p)`, where p is the momentum or `p=(h)/(lamda)` Since, `h=(h)/(2pi)" "p=(2pih)/(lamda)` |
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