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The de - Broglie wavelength `lambda` associated with an electron having kinetic energy `E` is given by the expressionA. `(h)/(sqrt( 2 m E))`B. `( 2h)/(m E)`C. `2 mhE`D. `( 2 sqrt(2 mE))/(h)` |
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Answer» Correct Answer - A `(1)/(2) mv^(2) = E rArr = mv = sqrt(2 m E) , :. E = (h)/( mv) = (h)/(sqrt( 2m E))` |
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