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The de - Broglie wavelength of a neutron in thermal equilibrium with heavy water at a temperature `T ("kelvin")` and mass `m`, isA. `lambda=h/(sqrt(3mKT))`B. `lambda=h/(sqrt(6mKT))`C. `lambda=h/(sqrt(5mKT))`D. `lambda=h/(sqrt(2mKT))` |
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Answer» Correct Answer - A As `1/2mv^(2)=3/2kT :. mv^(2)=3kT` or `m^(2)v^(2)=3mkT` or `mv=sqrt(3mkT)` `lambda=h/(mv)=h/(sqrt(3mkT))` |
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