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The de - Broglie wavelength of a particle moving with a velocity `2.25 xx 10^(8) m//s` is equal to the wavelength of photon. The ratio of kinetic energy of the particle to the energy of the photon is (velocity of light is `3 xx 10^(8) m//s`A. `1//8`B. `3//8`C. `5//8`D. `7//8` |
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Answer» Correct Answer - B `K_("particle") = (1)/(2) mv^(2)` also `lambda = (h)/(mv)` `rArr K_("particle") = (1)/(2) ((h)/(lambda v)).v^(2) = (vh)/(2 lambda)` ….(i) `K_(photon) = (hc)/(lambda)` ….(ii) `:. (K_("particle"))/(K_("particle")) = (v)/( 2c) = ( 2.25 xx 10^(8))/( 2 xx 3 xx 10^(8)) = (3)/(8)` |
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