1.

The de-Broglie wavelength of a particle of charge q and mass m is lamda. If its kinetic energy be K, then

Answer»

`lamda=(H)/(SQRT(MK))`
`lamda=(h)/(sqrt(mqK))`
`lamda=(sqrt(2mK))/(h)`
`lamda=(sqrt(mqK))/(h)`.

ANSWER :A


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