The de-Broglie wavelength of an electron in the first Bohr orbit isA. Equal to one fourth the circumference of the first orbitB. Equal to half the circyumference of the first orbitC. Equal to twice the circumference of the first orbitD. Equal to the circulference of the first orbit

The de-Broglie wavelength of an electron in the first Bohr orbit isA.

1.	The de-Broglie wavelength of an electron in the first Bohr orbit isA. Equal to one fourth the circumference of the first orbitB. Equal to half the circyumference of the first orbitC. Equal to twice the circumference of the first orbitD. Equal to the circulference of the first orbit
Answer» Correct Answer - D `mvr_(n) = (nh)/(2pi) rArr pr_(n) = (nh)/(2pi) rArr (h)/(lambda) xx r_(n) = (nh)/(2pi)` `rArr lambda = (2pir_(n))/(n)`, for first orbit `n = 1` so `lambda = 2pi r_(1)` `=` circumference of first orbit

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The de-Broglie wavelength of an electron in the first Bohr orbit isA. Equal to one fourth the circumference of the first orbitB. Equal to half the circyumference of the first orbitC. Equal to twice the circumference of the first orbitD. Equal to the circulference of the first orbit

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