1.

The de-Broglie wavelength of neutrons in thermal equilibrium is :

Answer»

`(30.8)/(sqrtT)Å`
`(3.08)/(SQRT(T))Å`
`(0.308)/(sqrt(T))Å`
`(0.0308)/(sqrt(T))Å`

SOLUTION :`LAMBDA=(h)/(sqrt(3mk//T))=(30*79)/(sqrt(T))Å=(30*8)/(s sqrt(T))Å`


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