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The decay constant, for a given radioactive sample is (0.3465)/(day). What percentage of this sample will get decayed in a period of 4 years? |
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Answer» Solution :Here `lambda = 0.3465/day, t = 4 years` `T_(1/2) = (0.6931)/(lambda) = (0.6931)/(0.3465) = 2 days` `n = (t)/(T_(1/2)) = (4)/(2) = 2` Hence sample left undecayed after a PERIOD of 4 years, `(N)/(N_(0)) = ((1)/(2))^(n) = ((1)/(2))^(2) = 1/4 = 25 %` |
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